15-3y=3(3y+1)-4(3y+1)-4(3y-6)

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Solution for 15-3y=3(3y+1)-4(3y+1)-4(3y-6) equation: 



15-3y=3(3y+1)-4(3y+1)-4(3y-6)

We move all terms to the left:

15-3y-(3(3y+1)-4(3y+1)-4(3y-6))=0



We calculate terms in parentheses: -(3(3y+1)-4(3y+1)-4(3y-6)), so:

3(3y+1)-4(3y+1)-4(3y-6)

We multiply parentheses

9y-12y-12y+3-4+24

We add all the numbers together, and all the variables

-15y+23

Back to the equation:

-(-15y+23)



We get rid of parentheses

-3y+15y-23+15=0

We add all the numbers together, and all the variables

12y-8=0

We move all terms containing y to the left, all other terms to the right

12y=8

y=8/12

y=2/3

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