15-4(x-3)=1+3x+2(x+4)

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Solution for 15-4(x-3)=1+3x+2(x+4) equation: 



15-4(x-3)=1+3x+2(x+4)

We move all terms to the left:

15-4(x-3)-(1+3x+2(x+4))=0

We multiply parentheses

-4x-(1+3x+2(x+4))+12+15=0



We calculate terms in parentheses: -(1+3x+2(x+4)), so:

1+3x+2(x+4)

determiningTheFunctionDomain
3x+2(x+4)+1

We multiply parentheses

3x+2x+8+1

We add all the numbers together, and all the variables

5x+9

Back to the equation:

-(5x+9)



We add all the numbers together, and all the variables

-4x-(5x+9)+27=0

We get rid of parentheses

-4x-5x-9+27=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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