15-5(4c-7)=49

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Solution for 15-5(4c-7)=49 equation: 



15-5(4c-7)=49

We move all terms to the left:

15-5(4c-7)-(49)=0

We add all the numbers together, and all the variables

-5(4c-7)-34=0

We multiply parentheses

-20c+35-34=0

We add all the numbers together, and all the variables

-20c+1=0

We move all terms containing c to the left, all other terms to the right

-20c=-1

c=-1/-20

c=1/20

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