15/(2x-1)=5/3/(x-4)

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Solution for 15/(2x-1)=5/3/(x-4) equation: 


D( x )

2*x-1 = 0

x-4 = 0

2*x-1 = 0

2*x-1 = 0

2*x-1 = 0 // + 1

2*x = 1 // : 2

x = 1/2

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:1/2) U (1/2:4) U (4:+oo)

15/(2*x-1) = (5/3)/(x-4) // - (5/3)/(x-4)

15/(2*x-1)-((5/3)/(x-4)) = 0

15/(2*x-1)+(-5/3)*(x-4)^-1 = 0

15/(2*x-1)-5/3/(x-4) = 0

(15*(x-4))/((2*x-1)*(x-4))+(-5/3*(2*x-1))/((2*x-1)*(x-4)) = 0

15*(x-4)-5/3*(2*x-1) = 0

35/3*x-175/3 = 0

(35/3*x-175/3)/((2*x-1)*(x-4)) = 0

(35/3*x-175/3)/((2*x-1)*(x-4)) = 0 // * (2*x-1)*(x-4)

35/3*x-175/3 = 0

35/3*x-175/3 = 0 // + 175/3

35/3*x = 175/3 // : 35/3

x = 175/3/35/3

x = 5

x = 5

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