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15/2x=6/x+9
We move all terms to the left:
15/2x-(6/x+9)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: x+9)!=0We get rid of parentheses
x∈R
15/2x-6/x-9=0
We calculate fractions
15x/2x^2+(-12x)/2x^2-9=0
We multiply all the terms by the denominator
15x+(-12x)-9*2x^2=0
Wy multiply elements
-18x^2+15x+(-12x)=0
We get rid of parentheses
-18x^2+15x-12x=0
We add all the numbers together, and all the variables
-18x^2+3x=0
a = -18; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-18)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-18}=\frac{-6}{-36} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-18}=\frac{0}{-36} =0 $
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