15/5x=4x/3x

Solution for 15/5x=4x/3x equation:

15/5x=4x/3x

We move all terms to the left:

15/5x-(4x/3x)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

15/5x-(+4x/3x)=0

We get rid of parentheses

15/5x-4x/3x=0

We calculate fractions


(-20x^2)/15x^2+45x/15x^2=0

We multiply all the terms by the denominator


(-20x^2)+45x=0

We get rid of parentheses

-20x^2+45x=0

a = -20; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·(-20)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*-20}=\frac{-90}{-40}
=2+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*-20}=\frac{0}{-40}
=0
$