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15/7x=3/x+2
We move all terms to the left:
15/7x-(3/x+2)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: x+2)!=0We get rid of parentheses
x∈R
15/7x-3/x-2=0
We calculate fractions
15x/7x^2+(-21x)/7x^2-2=0
We multiply all the terms by the denominator
15x+(-21x)-2*7x^2=0
Wy multiply elements
-14x^2+15x+(-21x)=0
We get rid of parentheses
-14x^2+15x-21x=0
We add all the numbers together, and all the variables
-14x^2-6x=0
a = -14; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-14)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-14}=\frac{0}{-28} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-14}=\frac{12}{-28} =-3/7 $
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