15/8y=21/(4y-12)

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Solution for 15/8y=21/(4y-12) equation:



15/8y=21/(4y-12)
We move all terms to the left:
15/8y-(21/(4y-12))=0
Domain of the equation: 8y!=0
y!=0/8
y!=0
y∈R
Domain of the equation: (4y-12))!=0
y∈R
We calculate fractions
60y/(-64y^2)+(-(21*8y)/(-64y^2)=0
We calculate terms in parentheses: +(-(21*8y)/(-64y^2), so:
-(21*8y)/(-64y^2
We add all the numbers together, and all the variables
-(+21*8y)/(-64y^2
We multiply all the terms by the denominator
-(+21*8y)
We get rid of parentheses
-21*8y
Wy multiply elements
-168y
Back to the equation:
+(-168y)
We get rid of parentheses
60y/(-64y^2)-168y=0
We multiply all the terms by the denominator
-168y*(-64y^2)+60y=0
We multiply parentheses
10752y^3+60y=0
We do not support eypression: y^3

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