15/m+5+10=2m

Solution for 15/m+5+10=2m equation:

15/m+5+10=2m

We move all terms to the left:

15/m+5+10-(2m)=0


Domain of the equation: m!=0

m∈R


We add all the numbers together, and all the variables

-2m+15/m+15=0

We multiply all the terms by the denominator


-2m*m+15*m+15=0

We add all the numbers together, and all the variables

15m-2m*m+15=0

Wy multiply elements

-2m^2+15m+15=0

a = -2; b = 15; c = +15;
Δ = b2-4ac
Δ = 152-4·(-2)·15
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{345}}{2*-2}=\frac{-15-\sqrt{345}}{-4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{345}}{2*-2}=\frac{-15+\sqrt{345}}{-4}
$