150=(2x+1)(x)/2

Solution for 150=(2x+1)(x)/2 equation:

150=(2x+1)(x)/2

We move all terms to the left:

150-((2x+1)(x)/2)=0

We multiply all the terms by the denominator


-((2x+1)x+150*2)=0


We calculate terms in parentheses: -((2x+1)x+150*2), so:

(2x+1)x+150*2

We add all the numbers together, and all the variables

(2x+1)x+300

We multiply parentheses

2x^2+x+300

Back to the equation:

-(2x^2+x+300)


We get rid of parentheses

-2x^2-x-300=0

We add all the numbers together, and all the variables

-2x^2-1x-300=0

a = -2; b = -1; c = -300;
Δ = b2-4ac
Δ = -12-4·(-2)·(-300)
Δ = -2399
Delta is less than zero, so there is no solution for the equation