150=2(3x-5)+2(x)

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Solution for 150=2(3x-5)+2(x) equation: 



150=2(3x-5)+2(x)

We move all terms to the left:

150-(2(3x-5)+2(x))=0



We calculate terms in parentheses: -(2(3x-5)+2x), so:

2(3x-5)+2x

We add all the numbers together, and all the variables

2x+2(3x-5)

We multiply parentheses

2x+6x-10

We add all the numbers together, and all the variables

8x-10

Back to the equation:

-(8x-10)



We get rid of parentheses

-8x+10+150=0

We add all the numbers together, and all the variables

-8x+160=0

We move all terms containing x to the left, all other terms to the right

-8x=-160

x=-160/-8

x=+20

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