150=45+(0.5x)+(2x)+(x)

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Solution for 150=45+(0.5x)+(2x)+(x) equation: 



150=45+(0.5x)+(2x)+(x)

We move all terms to the left:

150-(45+(0.5x)+(2x)+(x))=0

We add all the numbers together, and all the variables

-(45+(+0.5x)+2x+x)+150=0



We calculate terms in parentheses: -(45+(+0.5x)+2x+x), so:

45+(+0.5x)+2x+x

determiningTheFunctionDomain
(+0.5x)+2x+x+45

We add all the numbers together, and all the variables

3x+(+0.5x)+45

We get rid of parentheses

3x+0.5x+45

We add all the numbers together, and all the variables

3.5x+45

Back to the equation:

-(3.5x+45)



We get rid of parentheses

-3.5x-45+150=0

We add all the numbers together, and all the variables

-3.5x+105=0

We move all terms containing x to the left, all other terms to the right

-3.5x=-105

x=-105/-3.5

x=+30

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