150k2-216=0

Solution for 150k2-216=0 equation:

150k^2-216=0

a = 150; b = 0; c = -216;
Δ = b2-4ac
Δ = 02-4·150·(-216)
Δ = 129600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{129600}=360$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-360}{2*150}=\frac{-360}{300}
=-1+1/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+360}{2*150}=\frac{360}{300}
=1+1/5
$