152=(x-22+x)2

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Solution for 152=(x-22+x)2 equation: 



152=(x-22+x)2

We move all terms to the left:

152-((x-22+x)2)=0

We add all the numbers together, and all the variables

-((2x-22)2)+152=0



We calculate terms in parentheses: -((2x-22)2), so:

(2x-22)2

We multiply parentheses

4x-44

Back to the equation:

-(4x-44)



We get rid of parentheses

-4x+44+152=0

We add all the numbers together, and all the variables

-4x+196=0

We move all terms containing x to the left, all other terms to the right

-4x=-196

x=-196/-4

x=+49

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