1536=(x-8)(2x-8)(4)

Solution for 1536=(x-8)(2x-8)(4) equation:

1536=(x-8)(2x-8)(4)

We move all terms to the left:

1536-((x-8)(2x-8)(4))=0

We multiply parentheses ..

-((+2x^2-8x-16x+64)4)+1536=0


We calculate terms in parentheses: -((+2x^2-8x-16x+64)4), so:

(+2x^2-8x-16x+64)4

We multiply parentheses

8x^2-32x-64x+256

We add all the numbers together, and all the variables

8x^2-96x+256

Back to the equation:

-(8x^2-96x+256)


We get rid of parentheses

-8x^2+96x-256+1536=0

We add all the numbers together, and all the variables

-8x^2+96x+1280=0

a = -8; b = 96; c = +1280;
Δ = b2-4ac
Δ = 962-4·(-8)·1280
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-224}{2*-8}=\frac{-320}{-16}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+224}{2*-8}=\frac{128}{-16}
=-8
$