159=3x+3(3x+13)

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Solution for 159=3x+3(3x+13) equation:



159=3x+3(3x+13)
We move all terms to the left:
159-(3x+3(3x+13))=0
We calculate terms in parentheses: -(3x+3(3x+13)), so:
3x+3(3x+13)
We multiply parentheses
3x+9x+39
We add all the numbers together, and all the variables
12x+39
Back to the equation:
-(12x+39)
We get rid of parentheses
-12x-39+159=0
We add all the numbers together, and all the variables
-12x+120=0
We move all terms containing x to the left, all other terms to the right
-12x=-120
x=-120/-12
x=+10

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