15=(1+3m)=10(m-1)

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Solution for 15=(1+3m)=10(m-1) equation: 



15=(1+3m)=10(m-1)

We move all terms to the left:

15-((1+3m))=0

We add all the numbers together, and all the variables

-((3m+1))+15=0



We calculate terms in parentheses: -((3m+1)), so:

(3m+1)

We get rid of parentheses

3m+1

Back to the equation:

-(3m+1)



We get rid of parentheses

-3m-1+15=0

We add all the numbers together, and all the variables

-3m+14=0

We move all terms containing m to the left, all other terms to the right

-3m=-14

m=-14/-3

m=4+2/3

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