15=(1/2(4y-6))

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Solution for 15=(1/2(4y-6)) equation: 



15=(1/2(4y-6))

We move all terms to the left:

15-((1/2(4y-6)))=0



Domain of the equation: 2(4y-6)))!=0

y∈R



We multiply all the terms by the denominator


-((1+15*2(4y-6)))=0



We calculate terms in parentheses: -((1+15*2(4y-6))), so:

(1+15*2(4y-6))



We calculate terms in parentheses: +(1+15*2(4y-6)), so:

1+15*2(4y-6)

determiningTheFunctionDomain
15*2(4y-6)+1

Wy multiply elements

30y(4+1

Back to the equation:

+(30y(4+1)



We add all the numbers together, and all the variables

(30y5

Back to the equation:

-((30y5)

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