15=(2w-7)(w)

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Solution for 15=(2w-7)(w) equation:



15=(2w-7)(w)
We move all terms to the left:
15-((2w-7)(w))=0
We calculate terms in parentheses: -((2w-7)w), so:
(2w-7)w
We multiply parentheses
2w^2-7w
Back to the equation:
-(2w^2-7w)
We get rid of parentheses
-2w^2+7w+15=0
a = -2; b = 7; c = +15;
Δ = b2-4ac
Δ = 72-4·(-2)·15
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-13}{2*-2}=\frac{-20}{-4} =+5 $
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+13}{2*-2}=\frac{6}{-4} =-1+1/2 $

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