15=(30y/12+y)

Solution for 15=(30y/12+y) equation:

15=(30y/12+y)

We move all terms to the left:

15-((30y/12+y))=0


Domain of the equation: 12+y))!=0

We move all terms containing y to the left, all other terms to the right

y))!=-12

y!=-12/1

y!=-12

y∈R


We add all the numbers together, and all the variables

-((+y+30y/12))+15=0

We multiply all the terms by the denominator


-((+y+30y+15*12))=0


We calculate terms in parentheses: -((+y+30y+15*12)), so:

(+y+30y+15*12)

We add all the numbers together, and all the variables

(31y+180)

We get rid of parentheses

31y+180

Back to the equation:

-(31y+180)


We get rid of parentheses

-31y-180=0

We move all terms containing y to the left, all other terms to the right

-31y=180

y=180/-31

y=-5+25/31