15=(3x-3)+(2x+2)

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Solution for 15=(3x-3)+(2x+2) equation: 



15=(3x-3)+(2x+2)

We move all terms to the left:

15-((3x-3)+(2x+2))=0



We calculate terms in parentheses: -((3x-3)+(2x+2)), so:

(3x-3)+(2x+2)

We get rid of parentheses

3x+2x-3+2

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We get rid of parentheses

-5x+1+15=0

We add all the numbers together, and all the variables

-5x+16=0

We move all terms containing x to the left, all other terms to the right

-5x=-16

x=-16/-5

x=3+1/5

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