15=(4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2))/(22+x)

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Solution for 15=(4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2))/(22+x) equation: 



15=(4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2))/(22+x)

We move all terms to the left:

15-((4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2))/(22+x))=0



Domain of the equation: (22+x))!=0

We move all terms containing x to the left, all other terms to the right

x)!=-22

x!=-22/1

x!=-22

x∈R



We add all the numbers together, and all the variables

-((13x+952)/(x+22))+15=0

We multiply all the terms by the denominator


-((13x+952)+15*(x+22))=0



We calculate terms in parentheses: -((13x+952)+15*(x+22)), so:

(13x+952)+15*(x+22)

We multiply parentheses

(13x+952)+15x+330

We get rid of parentheses

13x+15x+952+330

We add all the numbers together, and all the variables

28x+1282

Back to the equation:

-(28x+1282)



We get rid of parentheses

-28x-1282=0

We move all terms containing x to the left, all other terms to the right

-28x=1282

x=1282/-28

x=-45+11/14

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