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15=(5/2)u
We move all terms to the left:
15-((5/2)u)=0
Domain of the equation: 2)u)!=0We add all the numbers together, and all the variables
u!=0/1
u!=0
u∈R
-((+5/2)u)+15=0
We multiply all the terms by the denominator
-((+5+15*2)u)=0
We calculate terms in parentheses: -((+5+15*2)u), so:u=0/-35
(+5+15*2)u
We add all the numbers together, and all the variables
35u
Back to the equation:
-(35u)
u=0
Równanie nie ma rozwiązania
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