15=(x+2)(x-2)(x)

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Solution for 15=(x+2)(x-2)(x) equation: 



15=(x+2)(x-2)(x)

We move all terms to the left:

15-((x+2)(x-2)(x))=0

We use the square of the difference formula

x^2+4+15=0

We add all the numbers together, and all the variables

x^2+19=0

a = 1; b = 0; c = +19;
Δ = b2-4ac
Δ = 02-4·1·19
Δ = -76
Delta is less than zero, so there is no solution for the equation

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