15=-5(r-6)-(3+r)

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Solution for 15=-5(r-6)-(3+r) equation: 



15=-5(r-6)-(3+r)

We move all terms to the left:

15-(-5(r-6)-(3+r))=0

We add all the numbers together, and all the variables

-(-5(r-6)-(r+3))+15=0



We calculate terms in parentheses: -(-5(r-6)-(r+3)), so:

-5(r-6)-(r+3)

We multiply parentheses

-5r-(r+3)+30

We get rid of parentheses

-5r-r-3+30

We add all the numbers together, and all the variables

-6r+27

Back to the equation:

-(-6r+27)



We get rid of parentheses

6r-27+15=0

We add all the numbers together, and all the variables

6r-12=0

We move all terms containing r to the left, all other terms to the right

6r=12

r=12/6

r=2

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