15=-7(y-3)+5y

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Solution for 15=-7(y-3)+5y equation: 



15=-7(y-3)+5y

We move all terms to the left:

15-(-7(y-3)+5y)=0



We calculate terms in parentheses: -(-7(y-3)+5y), so:

-7(y-3)+5y

We add all the numbers together, and all the variables

5y-7(y-3)

We multiply parentheses

5y-7y+21

We add all the numbers together, and all the variables

-2y+21

Back to the equation:

-(-2y+21)



We get rid of parentheses

2y-21+15=0

We add all the numbers together, and all the variables

2y-6=0

We move all terms containing y to the left, all other terms to the right

2y=6

y=6/2

y=3

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