15=1/2(x+2)-3

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Solution for 15=1/2(x+2)-3 equation:



15=1/2(x+2)-3
We move all terms to the left:
15-(1/2(x+2)-3)=0
Domain of the equation: 2(x+2)-3)!=0
x∈R
We multiply all the terms by the denominator
-(1+15*2(x+2)-3)=0
We calculate terms in parentheses: -(1+15*2(x+2)-3), so:
1+15*2(x+2)-3
determiningTheFunctionDomain 15*2(x+2)+1-3
We add all the numbers together, and all the variables
15*2(x+2)-2
Wy multiply elements
30x(x-2
Back to the equation:
-(30x(x-2)
We calculate terms in parentheses: -(30x(x-2), so:
30x(x-2
We calculate terms in parentheses: -(30x(x-2), so:
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We calculate terms in parentheses: -(30x(x-2), so:
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