15=2(-6-3c)+6c

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Solution for 15=2(-6-3c)+6c equation: 



15=2(-6-3c)+6c

We move all terms to the left:

15-(2(-6-3c)+6c)=0

We add all the numbers together, and all the variables

-(2(-3c-6)+6c)+15=0



We calculate terms in parentheses: -(2(-3c-6)+6c), so:

2(-3c-6)+6c

We add all the numbers together, and all the variables

6c+2(-3c-6)

We multiply parentheses

6c-6c-12

We add all the numbers together, and all the variables

-12

Back to the equation:

-(-12)



We add all the numbers together, and all the variables

27!=0

There is no solution for this equation

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