15=2(c+4)+3

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Solution for 15=2(c+4)+3 equation: 



15=2(c+4)+3

We move all terms to the left:

15-(2(c+4)+3)=0



We calculate terms in parentheses: -(2(c+4)+3), so:

2(c+4)+3

We multiply parentheses

2c+8+3

We add all the numbers together, and all the variables

2c+11

Back to the equation:

-(2c+11)



We get rid of parentheses

-2c-11+15=0

We add all the numbers together, and all the variables

-2c+4=0

We move all terms containing c to the left, all other terms to the right

-2c=-4

c=-4/-2

c=+2

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