15=2(x+4)+-3

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Solution for 15=2(x+4)+-3 equation: 



15=2(x+4)+-3

We move all terms to the left:

15-(2(x+4)+-3)=0

We use the square of the difference formula

-(2(x+4)-3)+15=0



We calculate terms in parentheses: -(2(x+4)-3), so:

2(x+4)-3

We multiply parentheses

2x+8-3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

-2x-5+15=0

We add all the numbers together, and all the variables

-2x+10=0

We move all terms containing x to the left, all other terms to the right

-2x=-10

x=-10/-2

x=+5

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