15=3(2x-11)2x

Solution for 15=3(2x-11)2x equation:

15=3(2x-11)2x

We move all terms to the left:

15-(3(2x-11)2x)=0


We calculate terms in parentheses: -(3(2x-11)2x), so:

3(2x-11)2x

We multiply parentheses

12x^2-66x

Back to the equation:

-(12x^2-66x)


We get rid of parentheses

-12x^2+66x+15=0

a = -12; b = 66; c = +15;
Δ = b2-4ac
Δ = 662-4·(-12)·15
Δ = 5076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5076}=\sqrt{36*141}=\sqrt{36}*\sqrt{141}=6\sqrt{141}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-6\sqrt{141}}{2*-12}=\frac{-66-6\sqrt{141}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+6\sqrt{141}}{2*-12}=\frac{-66+6\sqrt{141}}{-24}
$