15=3(7x-5)+9x

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Solution for 15=3(7x-5)+9x equation: 



15=3(7x-5)+9x

We move all terms to the left:

15-(3(7x-5)+9x)=0



We calculate terms in parentheses: -(3(7x-5)+9x), so:

3(7x-5)+9x

We add all the numbers together, and all the variables

9x+3(7x-5)

We multiply parentheses

9x+21x-15

We add all the numbers together, and all the variables

30x-15

Back to the equation:

-(30x-15)



We get rid of parentheses

-30x+15+15=0

We add all the numbers together, and all the variables

-30x+30=0

We move all terms containing x to the left, all other terms to the right

-30x=-30

x=-30/-30

x=1

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