15=3(c+4)

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Solution for 15=3(c+4) equation: 



15=3(c+4)

We move all terms to the left:

15-(3(c+4))=0



We calculate terms in parentheses: -(3(c+4)), so:

3(c+4)

We multiply parentheses

3c+12

Back to the equation:

-(3c+12)



We get rid of parentheses

-3c-12+15=0

We add all the numbers together, and all the variables

-3c+3=0

We move all terms containing c to the left, all other terms to the right

-3c=-3

c=-3/-3

c=1

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