15=4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2)/(22+x)

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Solution for 15=4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2)/(22+x) equation: 



15=4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2)/(22+x)

We move all terms to the left:

15-(4(2)+5(4)+13x+14(6)+21(5)+23(3)+26(2)/(22+x))=0



Domain of the equation: (22+x))!=0

We move all terms containing x to the left, all other terms to the right

x)!=-22

x!=-22/1

x!=-22

x∈R



We add all the numbers together, and all the variables

-(42+54+13x+146+215+233+262/(x+22))+15=0

We multiply all the terms by the denominator


-(42+54+13x+146+215+233+262+15*(x+22))=0



We calculate terms in parentheses: -(42+54+13x+146+215+233+262+15*(x+22)), so:

42+54+13x+146+215+233+262+15*(x+22)

determiningTheFunctionDomain
13x+15*(x+22)+42+54+146+215+233+262

We add all the numbers together, and all the variables

13x+15*(x+22)+952

We multiply parentheses

13x+15x+330+952

We add all the numbers together, and all the variables

28x+1282

Back to the equation:

-(28x+1282)



We get rid of parentheses

-28x-1282=0

We move all terms containing x to the left, all other terms to the right

-28x=1282

x=1282/-28

x=-45+11/14

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