15=4(2t+3)-3(4t-7)+10

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Solution for 15=4(2t+3)-3(4t-7)+10 equation: 



15=4(2t+3)-3(4t-7)+10

We move all terms to the left:

15-(4(2t+3)-3(4t-7)+10)=0



We calculate terms in parentheses: -(4(2t+3)-3(4t-7)+10), so:

4(2t+3)-3(4t-7)+10

We multiply parentheses

8t-12t+12+21+10

We add all the numbers together, and all the variables

-4t+43

Back to the equation:

-(-4t+43)



We get rid of parentheses

4t-43+15=0

We add all the numbers together, and all the variables

4t-28=0

We move all terms containing t to the left, all other terms to the right

4t=28

t=28/4

t=7

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