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15=5(2c-7)
We move all terms to the left:
15-(5(2c-7))=0
We calculate terms in parentheses: -(5(2c-7)), so:We get rid of parentheses
5(2c-7)
We multiply parentheses
10c-35
Back to the equation:
-(10c-35)
-10c+35+15=0
We add all the numbers together, and all the variables
-10c+50=0
We move all terms containing c to the left, all other terms to the right
-10c=-50
c=-50/-10
c=+5
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