15=5+2(2d-3)

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Solution for 15=5+2(2d-3) equation: 



15=5+2(2d-3)

We move all terms to the left:

15-(5+2(2d-3))=0



We calculate terms in parentheses: -(5+2(2d-3)), so:

5+2(2d-3)

determiningTheFunctionDomain
2(2d-3)+5

We multiply parentheses

4d-6+5

We add all the numbers together, and all the variables

4d-1

Back to the equation:

-(4d-1)



We get rid of parentheses

-4d+1+15=0

We add all the numbers together, and all the variables

-4d+16=0

We move all terms containing d to the left, all other terms to the right

-4d=-16

d=-16/-4

d=+4

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