15=5+4(2b-3)

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Solution for 15=5+4(2b-3) equation: 



15=5+4(2b-3)

We move all terms to the left:

15-(5+4(2b-3))=0



We calculate terms in parentheses: -(5+4(2b-3)), so:

5+4(2b-3)

determiningTheFunctionDomain
4(2b-3)+5

We multiply parentheses

8b-12+5

We add all the numbers together, and all the variables

8b-7

Back to the equation:

-(8b-7)



We get rid of parentheses

-8b+7+15=0

We add all the numbers together, and all the variables

-8b+22=0

We move all terms containing b to the left, all other terms to the right

-8b=-22

b=-22/-8

b=2+3/4

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