15=5+4(2d+3)

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Solution for 15=5+4(2d+3) equation: 



15=5+4(2d+3)

We move all terms to the left:

15-(5+4(2d+3))=0



We calculate terms in parentheses: -(5+4(2d+3)), so:

5+4(2d+3)

determiningTheFunctionDomain
4(2d+3)+5

We multiply parentheses

8d+12+5

We add all the numbers together, and all the variables

8d+17

Back to the equation:

-(8d+17)



We get rid of parentheses

-8d-17+15=0

We add all the numbers together, and all the variables

-8d-2=0

We move all terms containing d to the left, all other terms to the right

-8d=2

d=2/-8

d=-1/4

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