15=5+4(2d-5)

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Solution for 15=5+4(2d-5) equation:



15=5+4(2d-5)
We move all terms to the left:
15-(5+4(2d-5))=0
We calculate terms in parentheses: -(5+4(2d-5)), so:
5+4(2d-5)
determiningTheFunctionDomain 4(2d-5)+5
We multiply parentheses
8d-20+5
We add all the numbers together, and all the variables
8d-15
Back to the equation:
-(8d-15)
We get rid of parentheses
-8d+15+15=0
We add all the numbers together, and all the variables
-8d+30=0
We move all terms containing d to the left, all other terms to the right
-8d=-30
d=-30/-8
d=3+3/4

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