15=5-2(7q-3)

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Solution for 15=5-2(7q-3) equation: 



15=5-2(7q-3)

We move all terms to the left:

15-(5-2(7q-3))=0



We calculate terms in parentheses: -(5-2(7q-3)), so:

5-2(7q-3)

determiningTheFunctionDomain
-2(7q-3)+5

We multiply parentheses

-14q+6+5

We add all the numbers together, and all the variables

-14q+11

Back to the equation:

-(-14q+11)



We get rid of parentheses

14q-11+15=0

We add all the numbers together, and all the variables

14q+4=0

We move all terms containing q to the left, all other terms to the right

14q=-4

q=-4/14

q=-2/7

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