15=6+4(2d-3)

Solution for 15=6+4(2d-3) equation:

15=6+4(2d-3)

We move all terms to the left:

15-(6+4(2d-3))=0


We calculate terms in parentheses: -(6+4(2d-3)), so:

6+4(2d-3)

determiningTheFunctionDomain
4(2d-3)+6

We multiply parentheses

8d-12+6

We add all the numbers together, and all the variables

8d-6

Back to the equation:

-(8d-6)


We get rid of parentheses

-8d+6+15=0

We add all the numbers together, and all the variables

-8d+21=0

We move all terms containing d to the left, all other terms to the right

-8d=-21

d=-21/-8

d=2+5/8