15=g-4/5g

Solution for 15=g-4/5g equation:

15=g-4/5g

We move all terms to the left:

15-(g-4/5g)=0


Domain of the equation: 5g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

-(+g-4/5g)+15=0

We get rid of parentheses

-g+4/5g+15=0

We multiply all the terms by the denominator


-g*5g+15*5g+4=0

Wy multiply elements

-5g^2+75g+4=0

a = -5; b = 75; c = +4;
Δ = b2-4ac
Δ = 752-4·(-5)·4
Δ = 5705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{5705}}{2*-5}=\frac{-75-\sqrt{5705}}{-10}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{5705}}{2*-5}=\frac{-75+\sqrt{5705}}{-10}
$