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15a^2-13a=0
a = 15; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·15·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*15}=\frac{0}{30} =0 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*15}=\frac{26}{30} =13/15 $
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