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15h^2+14h-8=0
a = 15; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·15·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*15}=\frac{-40}{30} =-1+1/3 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*15}=\frac{12}{30} =2/5 $
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