15j+6=3(2j-4)

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Solution for 15j+6=3(2j-4) equation: 



15j+6=3(2j-4)

We move all terms to the left:

15j+6-(3(2j-4))=0



We calculate terms in parentheses: -(3(2j-4)), so:

3(2j-4)

We multiply parentheses

6j-12

Back to the equation:

-(6j-12)



We get rid of parentheses

15j-6j+12+6=0

We add all the numbers together, and all the variables

9j+18=0

We move all terms containing j to the left, all other terms to the right

9j=-18

j=-18/9

j=-2

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