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15m(m+3)=11m-15
We move all terms to the left:
15m(m+3)-(11m-15)=0
We multiply parentheses
15m^2+45m-(11m-15)=0
We get rid of parentheses
15m^2+45m-11m+15=0
We add all the numbers together, and all the variables
15m^2+34m+15=0
a = 15; b = 34; c = +15;
Δ = b2-4ac
Δ = 342-4·15·15
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-16}{2*15}=\frac{-50}{30} =-1+2/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+16}{2*15}=\frac{-18}{30} =-3/5 $
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