15m+6(2m-4)=19m+2(-18+m)

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Solution for 15m+6(2m-4)=19m+2(-18+m) equation: 



15m+6(2m-4)=19m+2(-18+m)

We move all terms to the left:

15m+6(2m-4)-(19m+2(-18+m))=0

We add all the numbers together, and all the variables

15m+6(2m-4)-(19m+2(m-18))=0

We multiply parentheses

15m+12m-(19m+2(m-18))-24=0



We calculate terms in parentheses: -(19m+2(m-18)), so:

19m+2(m-18)

We multiply parentheses

19m+2m-36

We add all the numbers together, and all the variables

21m-36

Back to the equation:

-(21m-36)



We add all the numbers together, and all the variables

27m-(21m-36)-24=0

We get rid of parentheses

27m-21m+36-24=0

We add all the numbers together, and all the variables

6m+12=0

We move all terms containing m to the left, all other terms to the right

6m=-12

m=-12/6

m=-2

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