15p+3p2-4p+7p2=0

Solution for 15p+3p2-4p+7p2=0 equation:

15p+3p^2-4p+7p^2=0

We add all the numbers together, and all the variables

10p^2+11p=0

a = 10; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·10·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*10}=\frac{-22}{20}
=-1+1/10
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*10}=\frac{0}{20}
=0
$