15r2+37r-8=0

Solution for 15r2+37r-8=0 equation:

15r^2+37r-8=0

a = 15; b = 37; c = -8;
Δ = b2-4ac
Δ = 372-4·15·(-8)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-43}{2*15}=\frac{-80}{30}
=-2+2/3
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+43}{2*15}=\frac{6}{30}
=1/5
$